(A) We Know,
According to De-Broglie equation:
\(p = \frac h\lambda \)
p = momentum
\(p = \frac{ h\times c}{\lambda \times c} = \frac{\text{energy}}c\)
\(p = \frac{9\times 1.6 \times 10^{-19}}{3 \times 10^8}\)
\(p = \frac{14.4 \times 10^{-27}}{3}\)
\(p = 4.8 \times 10^{-27}\ kg−m/s\)