Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
80 views
in Statistics by (15 points)

Please log in or register to answer this question.

1 Answer

0 votes
by (395 points)

To find the mean, median, and mode, we first need to calculate the class marks, which are the midpoints of each class interval.

Class Interval | Class Mark

20-30 | (20+30)/2 = 25

30-40 | (30+40)/2 = 35

40-50 | (40+50)/2 = 45

50-60 | (50+60)/2 = 55

60-70 | (60+70)/2 = 65

70-80 | (70+80)/2 = 75

80-90 | (80+90)/2 = 85

Next, we calculate the total number of students:

Total students = 8 + 15 + 100 + 150 + 140 + 61 + 20 = 494

Now, let's calculate the mean, median, and mode:

  1. Mean:

Mean = (Sum of (Class Mark * Number of Students)) / Total Students

Mean = (258 + 3515 + 45100 + 55150 + 65140 + 7561 + 85*20) / 494

Mean ≈ 59.55

  1. Median:

To find the median, we first need to arrange the class marks in ascending order:

25, 35, 45, 55, 65, 75, 85

Since there are an even number of class marks (7), the median will be the average of the middle two class marks. In this case, the middle two class marks are 55 and 65.

Median = (55 + 65) / 2

Median = 60

  1. Mode:

The mode is the class mark with the highest number of students. Looking at the given data, the class mark with the highest number of students is 65 (with 140 students).

Mode = 65

In summary:

Mean ≈ 59.55

Median = 60

Mode = 65

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...