If the foci of the hyperbola are same as that of ellipse x^2 /9 + y^2 /25 =1 and the eccentricity of the hyperbola is 15/8 times the eccentricity of the ellipse,then the smaller focal distance of the point (√2,14/3 √2/√5) on the hyperbola is equal to
A- 7√2/√5 - 8/3
B- 14√2/√5 -4/3
C- 14√2/√5- 16/3
D- 7√2/√5 + 8/3
