Question

If product of the roots of the quadratic equation \(x^2 - 5x + p = 10\) is -4, then the value of p is

(A) 4

(B) 5

(C) 6

(D) 8

Answer 1

Correct option is (C) 6

Given,

\(x^{2}-5 x+p=10\)

\(x^{2}-5 x+(p-10)=0 \)

\(\alpha \beta =\frac{c}{a}\)

\(-4 =\frac{p-10}{1} \)

\(-4 =p-10\)

\(-4+10 =p\)

\(\therefore p=6\)