Question

If one root of the quadratic equation \(y^2 + 3y - 18 = 0\) is - 6 then its another root is

(A) 3

(B) -3

(C) 6

(D) 5

Answer 1

Correct option is (A) 3

Since, -6 is a root of quadratic equation \(y^{2}+3 y-18=0\)

Here, \(a=1, b=3\) and \(c=-18\)

\(\alpha \beta =\frac{c}{a}\)

\(-6 \times \beta =\frac{-18}{1} \)

\(\beta =\frac{-18}{-6} \)

\(\therefore \beta =3\)

\(\therefore\) The another root is 3.