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0 votes
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in Mathematics by (45.1k points)
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The roots of the quadratic equation \(ax^2 - bx - c = 0, a \ne 0\) are

(A) \(\frac{-b \pm \sqrt{b^2 - 4ac}}{2a}\)

(B) \(\frac{b \pm \sqrt{b^2 + 4ac}}{2a}\)

(C) \(\frac{-b \pm \sqrt{b^2 + 4ac}}{2a}\)

(D) \(\frac{b \pm \sqrt{b^2 - 4ac}}{2a}\)

2 Answers

+1 vote
by (44.9k points)
selected by
 
Best answer

Correct option is (B) \(\frac{b \pm \sqrt{b^2 + 4ac}}{2a}\)

The roots of a quadratic equations \(a x^{2}-b x-c=0\) are \(x =\frac{b \pm \sqrt{b^2 + 4ac}}{2a}\).

+1 vote
by (15.4k points)

AnkushLather, hello

For the quadratic equation that you have asked about, namely

ax2 - bx - c = 0

The correct option is (B)  \(x = {b \pm \sqrt{b^2+4ac} \over 2a}\) 

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