Question

If a digit is chosen at random from the digits 1, 2, 3, 4, 5, 6, 7, 8, 9; then the probability that this digit is an odd prime number is:

(A) \(\frac 13\)

(B) \(\frac 23\)

(C) \(\frac 49\)

(D) \(\frac 59\)

Answer 1

Correct option is (A) \(\frac 13\)

Total number of digits is 9.

Digit that are odd prime number are 3, 5, 7.

Total number of odd prime digits is 3.

\(\therefore \text{Probability} = \frac{\text{Number of favourable event}}{\text{Total number of event}}\)

\(= \frac 39\)

\(= \frac 13\)