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in Some basic concepts in chemistry by (15 points)

The number of atoms in 8 g of sodium is \(x \times 10 ^{23}\). The value of x is                         . (Nearest integer)

[Given : \(N_{A} = 6.02\times 10^{23} \mathrm{mol^{-1}} \)

Atomic mass of Na = 23.0 u]

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1 Answer

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by (15.5k points)

Ankur Tiwari, hello

1 mol of Na or 23 g of Na has 6.02×1023 atoms.
8 g of Na has: 
8/23 × 6.02×1023 atoms
⇒2.09×1023 atoms
≈2×1023 atoms
The value of x is: 2

Please let me know if this helps

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