Find the spin only magnetic moment (nearest integer) of M in MO4^2-, M being the atom having least atomic radii among Sc, Ti, V, Cr, Mn, Zn

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UdaySingh · Answer 1 · 2024-04-10T04:59:58+0000

Correct answer is: 0

Radii → Sc > Ti > Mn ≃ Zn > V > Cr

So, M is Cr.

\(\overset{+6}{Cr}O_4^{2-} : \overset{+6}{Cr}\rightarrow [Ar]4s^03d^0⇒\) zero unpaired electron μ_spin = 0