Points A(-1, y) and B(5, 7) lie on a circle with centre O(2, -3y).
Which means: OA = OB or OA2 = OB2
using distance formula, we get
(-1 - 2)2 + (y - (-3y))2 = (5 - 2)2 + (7 - (-3y))2
9 + 16y2 = 9 + (7 + 3y)2
16y2 = 49 + 42y + 9y2
7y2 - 42y - 49 = 0
7(y2 - 6y - 7) = 0
y2 - 7y + y - 7 = 0
y(y-7) + 1(y - 7) = 0
(y + 1) (y - 7) = 0
Therefore, y = 7 or y = -1
When y = -1
The coordinate of O, A and B are O(2, 3), A(-1, -1) and B(5, 7) respectively.
\(\therefore\) Radius = \(OA = \sqrt{(2 + 1)^2 + (3 + 1)^2}\)
\(= \sqrt{(3)^2 + (4)^2}\)
\(= \sqrt {9 + 16}\)
\(= \sqrt{25}\)
\(= 5\)
When y = 7
The coordinate of O, A and B are O(2, -21), A(-1, 7) and B(5, 7) respectively.
\(\therefore\) Radius = \(OA = \sqrt{(2 + 1)^2 + (-21-7)^2}\)
\(= \sqrt{(3)^2 + (-28)^2}\)
\(= \sqrt{9 + 784}\)
\(= \sqrt{793}\)