Question

4 foot value of kr root se quartic equation 3x square - 2K X + 27 = 0

Answer 1

The given equation 3x² + 2kx + 27 = 0

Here, a = 3, b = 2k, c = 27

It is given that roots are real and equal.

∴ b² − 4ac = 0

⇒ (2k)² − 4(3)(27) = 0

⇒ 4k² − 324 = 0

⇒ 4k² = 324

⇒ k² = 81

∴ k = ±9