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If work function of a metal is 2.13 eV and energy per photon of incident light is 3.13 eV, then maximum

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If work function of a metal is 2.13 eV and energy per photon of incident light is 3.13 eV, then maximum kinetic energy of photoelectrons (in eV) will be______.

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1 Answer

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by (32.9k points)

Correct answer is : 1

KEmax = hr – \(\phi\)0

= (3.13 – 2.13) eV 

= 1 eV

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