Correct option is (A) 1
The given lines are
\(4x + 3y -12 = 0\)
\(4x + 3y -17 = 0\)
As we know that distance between the parallel lines (d) is given as-
\(d = \frac{|c_2 - c_1|}{\sqrt{a^2 + b^2}}\)
Therefore,
\(d = \frac{|-17 -(- 12)|}{\sqrt{4^2 + 3^2}}\)
\(= \frac {|-17 + 12|}{\sqrt{1 6 + 9}}\)
\(= \frac {|-5|}{\sqrt{25}}\)
\(= \frac {5}{5}\)
\(= 1\)
