Question

Volume of 4.4 g CO₂ at STP is

(A) 22.4 L

(B) 2.24 L

(C) 224 L

(D) 44.8 L

Answer 1

Correct option is (B) 2.24 L

As given,

Mole = \(\frac{\text{mass}}{\text{Molar mass}} = \frac{4.4}{44} = 0.1\)

\(V_{CO_2} = n \times \text{Molar volume}\)

\(= 0.1 \times 22.4 \)

\(= 2.24 \ L\)