If equilibrium constant for the reaction 2AB ⇌ A2 + B2 is 49, then the equilibrium constant for the reaction

Question

If equilibrium constant for the reaction \(2AB \rightleftharpoons A_2 + B_2\) is 49, then the equilibrium constant for the reaction \(AB \rightleftharpoons \frac 12 A_2 + \frac 12B_2\) would be

(A) 2401

(B) 49

(C) 7

(D) 3-2

Answer 1

Correct option is (C) 7

\(K2 = K1^{ 1/2}\)

\(= 49^{1/2}\)

\(= 7\)