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4.25 ग्राम अमोनिया में अणुओं की संख्या है

(A) \(1.0 \times 10^{23}\)

(B) \(1.5 \times 10^{23}\)

(C) \(2.0 \times 10^{23}\)

(D) \(2.5\times 10^{23}\)

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सही विकल्प है (B) 1.5 x 1023

चूंकि NH3 के 17 ग्राम में 1 मोल है।

4.25 ग्राम में मोलों की संख्या = \(\frac {4.25}{17}\)

अणुओं की संख्या = \(\frac{4.25}{17} \times 6.023 \times 10^{23}= 1.5 \times 10^{23}\)

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