Question

Find the derivative of sin x3 with respect ot x2 .

Answer 1

Let \(y= \sin x^3, z= x^2\)

\(\frac{dy}{dx} = 3x^2 \cos x^3; \frac{dz}{dx} = 2x\)

⇒ \(\frac{dy}{dz} = \frac{\frac{dy}{dx}}{\frac{dz}{dx}} \)

\(= \frac{3x^2 \cos x^3}{2x}\)