Question

For hydrogen atom, energy of an electron in first excited state is - 3.4 eV, K.E. of the same electron of hydrogen atom is x eV. Value of x is _____ \(\times 10 ^{-1} eV.\) (Nearest integer)

Answer 1

Correct answer is : 34

KE = - T. E.

\(=-(-3.4) = + 3.4 \,ev\)

\(= 34 \times 10 ^{-1}\)