Correct option is (2) 960
\(C_6 H_{12} O_{6}+ 6O_{2} \rightarrow 6CO_{2}+ 6 H_2 O\)
Given Mass of glucose = 900 gram
Molar mass of glucose = 180 gm/mole
So, moles of glucose \(\Rightarrow \frac {900}{180} = 5\)
1 mole of glucose require 6 moles of oxygen gas
So, 5 moles of glucose will require 30 moles of oxygen gas
Moles of oxygen gas = 30
Molar mass of oxygen gas \(\Rightarrow\) 32 g/mol
So, mass of oxygen gas required \(\Rightarrow\) 30 \(\times\) 32
\(\Rightarrow\) 960 gram.