Question

A body of mass M thrown horizontally with velocity v from the top of the tower of height H touches the ground at a distance of 100 m from the foot of the tower. A body of mass 2M thrown at a velocity \(\frac{v}{2}\) from the top of the tower of height 4H will touch the ground at a distance of _________ m

Answer 1

Correct answer is : 100 

\(100=v \sqrt{\frac{2 \mathrm{H}}{\mathrm{g}}} ; \quad \mathrm{x}=\frac{v}{2} \sqrt{\frac{2(4 \mathrm{H})}{\mathrm{g}}}=v \sqrt{\frac{2 \mathrm{H}}{\mathrm{g}}}\)

\(\Rightarrow \mathrm{x}=100\)