a man in a balloon rising vertically with an acc. of 5 m/s^2 release a ball 2 sec after the balloon go from the ground . wht is the greatest ht

Question

A man in a balloon rising vertically with an acceleration of 5ms⁻² releases a ball 2 second after the balloon is let go from the ground. The greatest height above the ground reached by the ball is :

Comments

Kindly complete question to enable answering

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its ur problem that u r not getting the question but pls kindly check that one elder didi has answered this question. thanks for the feedback

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Yes I agree. I have given comments reading what is there was in green box above. Apologies for comment. It was fairly straight forward question.
Thanks

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no its okay , i hv asked u for one more question regarding one another problem

Answer 1

Height traveled by ball (with balloon) in 2 sec             

h₁=1/2at²=1/2×5×2²= 10 m

Velocity of the balloon after 2 sec

v = at = 5×2 = 10 m/s

Now if the ball is released from the balloon then it acquire same velocity in upward direction.

Let it move up to maximum height h₂

v²=u²−2gh₂ 

=> 0=(10)²−2×(10)×h₂

∴ h₂ = 5m

Greatest height above the ground reached by the ball = h₁+h₂ = 10+5 = 15 m

Comments

thanks a lot didi

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You're welcome :)