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+1 vote
981 views
in Mathematics by (115 points)
In how many way,a party of 3 or more can be selected from 8 person

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1 Answer

+1 vote
by (14.7k points)

3 or more persons to select

i.e 8C3+8C4+8C5+8C6+8C7+8C8

Now, 8C0+8C1+8C2+8C3+8C4+8C5+8C6+8C7+8C8-8C0-8C1-8C2

We know that

nC0 + nC1 + nC2 + ... + nCn = 2n

8C0+8C1+8C2+8C3+8C4+8C5+8C6+8C7+8C8 = 28

28-(8C0+8C1+8C2)

256-(1+8+28)

256-37

219 ways

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