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0.15 g of a substance dissolved in 15 g of a solvent boiled at a temperature higher by 0.216ºC than that of the pure solvent, find

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0.15 g of a substance dissolved in 15 g of a solvent boiled at a temperature higher by 0.216ºC than that of the pure solvent, find out the molecular weight of the substance (Kb for solvent is 2.16ºC).

(a) 1.01  (b) 10.1  (c) 100 (d) 10

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Correct option  (c) 100

Explanation:

M = Kb .WB .1000/ ΔTb . 

WA = 2.16 ´ 0.15 ´ 1000 / 0.216 ´ 15 = 100

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