The shape of the string is drawn at t = 0 and the area of the pulse enclosed by the string and the x-axis is measured. It will be equal to

Question

A pulse is started at a time t = 0 along the +x direction on a long, taut string. The shape of the pulse at t = 0 is given by function f(x) with

here f and x are in centimeters. The linear mass density of the string is 50 g/m and it is under a tension of 5N,

The shape of the string is drawn at t = 0 and the area of the pulse enclosed by the string and the x-axis is measured. It will be equal to

(A) 2 cm² 

(B) 2.5 cm² 

(C) 4 cm² 

(D) 5 cm² 

Answer 1

Correct option: (B) 2.5 cm²

Explanation:

Shape of the pulse at t = 0

That is a triangular pulse

Area of the pulse = 1/2 [ (4 x 1) ] = 5/2 am²