Let us first assume that 0.01 M AgNO3 shall combine with 0.02 NH3 to form 0.01 M Ag(NH3)2+ and the consider its dissociation.
Further, ionic product of AgCl = [Ag+ ] [Cl– ] = (6.12 × 10–10) (0.01) = 6.12 × 10–12
Because the ionic product is smaller than Ksp = 1.8 × 10–10, no precipitate should form.