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∫((sinθ + cosθ)/√(sin2θ))dθ is equal to

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+1 vote
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in Integrals calculus by (41.7k points)

 ∫((sinθ + cosθ)/√(sin2θ))dθ is equal to

(A) sin-1(sinθ + cosθ)

(B) sin-1θ(sinθ - cosθ)

(C) sin-1(cosθ - sinθ)

(D) None of these  

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1 Answer

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Best answer

Answer is (B) sin-1θ(sinθ - cosθ)

From given equation, we have

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