Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
5.7k views
in Complex number and Quadratic equations by (53.5k points)

Let S be the set of values of a for which 2 lies between the roots of quadratic equation x2 + (a + 2)x - (a + 3)x = 0. Then S is given by

(A)  (−∞, −5)

(B)  (5, ∞)

(C)  (−∞, −5]

(D)  [5, ∞)

1 Answer

+1 vote
by (53.3k points)
selected by
 
Best answer

Correct option (A)  (- ∞,-5)

See Fig. 

x2 + (a + 2)x - (a + 3) = 0

As f(2) < 0, we have

⇒ 4 + 2(a + 2) - (a + 3) < 0

⇒ a + 5 < 0

⇒ a < − 5

⇒ a ∈(-∞, -5)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

...