Question

State Kirchhoff’s rules. Apply Kirchhoff’s rules to the loops ACBPA and ACBQA to write the expressions for the currents I₁, I₂ and I₃ in the network.

Answer 1

From Kirchhoff’s law

I₃ = I₁ + I₂ …(i)

Applying Kirchhoff’s II law to loop ACBPA

- 12I₃ - 0.5I₁ + 6 = 0

0.5I₁ + 12I₃ = 6 .....(ii)

Applying Kirchhoff’s II law to loop ACBQA

- 12I₃ - 1I₂ + 10 = 0

I₂ + 12I₃ = 10 ....(iii)