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If y = acos(logx) + bsin(logx) prove that x2y2+xy1 + y = 0

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Best answer

If y = acos(logx) + bsin(logx)

xy1 = -asin(logx) + bcos(logy) 

again diff. w.r it. x. 

x2y2 + xy1 = – y ⇒ x2y2 + xy1 + y = 0

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