(i) f (x) = (2x – 1)2 + 3
For all values of x, f (x) > 3 (2x – 1)2 + 3 > 3
∴ minimum value is 3 when 2x -1 = 0 is x = \(\frac{1}{2}\)however the function has no maximum values as f (x) → ∞ as |x| ∞
(ii) f(x) = 9x2 + 12x + 2
However there is no maximum values.
(iii) f(x) = – (x – 1)2 + 10
f(x)= 10 – (x – 1)2
10 – (x – 1)2 < 10
f(x) has a maximum value when x – 1 = 0,x= 1.
how ever f (x) has no minimum value.
(iv) g(x) = x3 + 1 as → ∞ g (x) → ∞ and a s → ∞, g(x) → – ∞
∴ g(x) has neither minimum value nor maximum value.