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in Linear Equations by (56.4k points)

4 tables and 3 chairs, together, cost ₹ 2250 and 3 tables and 4 chairs cost ₹ 1950. Find the cost of 2 chairs and 1 table.

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Let’s assume the cost of 1 table is ₹ x and cost of 1 chair is ₹ y. 

Then, according to the question 

4x + 3y = 2250 … (i) 

3x + 4y = 1950 … (ii) 

On multiplying (i) with 3 and (ii) with 4, 

We get, 

12x + 9y = 6750 … (iii) 

12x + 16y = 7800 … (iv) 

Now, subtracting equation (iv) from (iii), We get, 

-7y = -1050 

y = 150 

Using y = 150 in (i), we find x 

4x + 3(150) = 2250 

4x = 2250 – 450 

x = 1800/ 4 

⇒ x = 450 

From the question, it’s required to find the value of (x + 2y) 

⇒ 450 + 2(150) = 750 

Therefore, the total cost of 2 chairs and 1 table is ₹ 750.

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