Given: AD = 2.5 cm, AE = 3.75 cm and BD = 3 cm
Required to find AC.
By using Thales Theorem, [As DE ∥ BC]
\(\frac{AD}{BD} = \frac{AE}{CE}\)
\(\frac{2.5}{3} = \frac{3.75}{CE}\)
2.5 x CE = 3.75 x 3
CE = \(\frac{3.75 \times 3}{2.5}\)
CE = \(\frac{11.25}{2.5}\)
CE = 4.5
Now, AC = 3.75 + 4.5
∴ AC = 8.25 cm.