Here we have,
LHS = x2 − 3√3x + 6
Substituting x = √3 in LHS, we get
(√3)2 − 3√3(√3) + 6
⇒ 3 – 9 + 6 = 0 = RHS
⇒ LHS = RHS
Thus, x = √3 is a solution of the given equation.
Similarly,
Substituting x = −2√3 in LHS, we get
(-2√3)2 − 3√3(-2√3) + 6
⇒ 12 + 18 + 6 = 36 ≠ RHS
⇒ LHS ≠ RHS
Thus, x = −2√3 is not a solution of the given equation.