Here we have,
LHS = x2 – √2x – 4
Substituting x = -√2 in LHS, we get
(-√2)2 − √2(-√2) – 4
⇒ 4 + 2 – 4 = 2 ≠ RHS
⇒ LHS ≠ RHS
Thus, x = -√2 is a solution of the given equation.
Similarly,
Substituting x = −2√2 in LHS, we get
(-2√2)2 − √2(-2√2) – 4
⇒ 8 + 4 – 4 = 8 ≠ RHS
⇒ LHS ≠ RHS
Thus, x = −2√2 is not a solution of the given equation.