Given,
kx2 + 6x + 1 = 0
It’s of the form of ax2 + bx + c = 0
Where, a =k, b = 6, c = 1
For the given quadratic equation to have real roots D = b2 – 4ac > 0
D = (6)2 – 4(1)(k) > 0
⇒ 36 – 4k > 0
⇒ 4k < 36
⇒ k < 9
The value of k should be lesser than 9 to have real and distinct roots.
