Distance travelled by aeroplane towards North is 1\(\frac{1}{2}\)hours :
= 1000 x 1\(\frac{1}{2}\)
= 1000 x \(\frac{3}{2}\)
= 1500 km.
Distance travelled by aeroplane towards West in 1\(\frac{1}{2}\)Hours :
= 1200 x 1\(\frac{1}{2}\)
= 1200 x \(\frac{3}{2}\)
= 1800 km.
In ⊥∆AOB,
AB2 = OA2 + OB2
= (1500)2 + (1800)2
= 2250000 + 3240000 = 5490000
∴ Two planes are 300V 6T km. apart after 14 hours