Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.0k views
in Physics by (61.2k points)

An object 5.0 cm in length is placed at a distance of 20 cm in front of a convex mirror of radius of curvature 30 cm. Find the position of the image, its nature and size.

1 Answer

+1 vote
by (57.3k points)
selected by
 
Best answer

Object distance, u = 20 cm

Height of object h = 5 cm

Radius of curvature R = 30 cm

R = 2f, f = 15 cm

As per mirror formula

Positive sign indicates image is formed behind the mirror

Magnification = \(\frac{Image\,distance}{Object\,distance}\) = \(\frac{h^1}{h}\)

h1 = m × h = 0.428 × 5 = 2.14 cm

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...