Question

Redraw the circuit of Question 1, putting in an ammeter to measure the current through the resistors and a voltmeter to measure the potential difference across the 12Ω resistor. What would be the readings in the ammeter and the voltmeter?

Answer 1

Resistance, R = 5 + 8 + 12

= 25Ω

I = \(\frac{V}{R}\) = \(\frac{6}{25}\) = 0.24A

As per ohm’s law = 0.24A

V₁ = IR

Potential difference

V₁ = IR = 0.24 × 12 = 2.88 V.

reading in ammeter = 0.24A

reading in voltmeter = 2.88 V.