Question

A battery of 9 V is connected in series with resistors of 0.2Ω, 0.3Ω, 0. 4Ω, 0.5Ω and 12Ω, respectively. How much current would flow through the 12Ω resistor?

Answer 1

A battery of 9V is connected in series with resistors 0.2Ω, 0.3Ω, 0.4Ω,

R = 0.2 + 0.3 + 0.4 + 0.5 + 12

= 13.4Ω.

V = 9V

I = \(\frac{9}{13.4}\) = 0.671A

∴ 12 V battery, 0.671 A current flows.