R = 20 cm
r = 8 cm
h = 20 cm
∴ Slant height,
Quantity of milk in the container
= \(\frac{10449.82}{1000}\)
Cost of 1 litre of milk is Rs. 20,
Cost of 10.45 litres of milk ……. ??
∴ 20 × 10.45 = Rs. 209.
Cost of metal sheet = π(R + r) + πr2
= π {20 × (20 + 8) + (8)2} = 3.14 × 624 = 1959.36 cm2 .
∴ Cost of preparing metallic container :
For 100 cm2 Rs. 8,
∴ For 1959.36 cm2 …… ??
= 8 x \(\frac{1159.36}{100}\)
= Rs. 156.75.