Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
1.8k views
in Gauss’s Law and its Applications by (61.2k points)

Two metallic surface of area 1 m are placed at 0.05 m parallel to each other. Both have same magnitude of charges but opposite in direction. If the electric field between them is 55 V/m, then what would be charge on each?

1 Answer

+1 vote
by (57.3k points)
selected by
 
Best answer

At the point C between both the plates, the electric field intensity due to both plates \(\vec {E_1}\) and \(\vec{E_2}\) will be in same direction.
Therefore, resultant electric field

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...