Question

The time required for 10% completion of a first order reaction at 298 K is equal to that required for its 25% completion at 308 K. If the value of A is 4 x 10¹⁰ s^-1, Calculate the value of k at 318 K and E_a.

Answer 1

= 10.6021 – 12.5843= – 1.9822
k = Antilog (-1.9822) = Antilog (2.0178)
k = 1.042 x 10^-2 s^-1