Use app×
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE
0 votes
2.4k views
in Chemistry by (46.2k points)

Write a balanced chemical equation for each of the following reactions and also classify them. 

(a) Lead acetate solution is treated with dilute hydrochloric acid to form lead chloride and acetic acid solution. 

(b) A piece of sodium metal is added to absolute ethanol to form sodium ethoxide and hydrogen gas.

(c) Iron (III) oxide on heating with carbon monoxide gas reacts to form solid iron and liberates carbon dioxide gas. 

(d) Hydrogen sulphide gas reacts with oxygen gas to form solid sulphur and liquid water

1 Answer

+1 vote
by (45.7k points)
selected by
 
Best answer

(a) Pb(CH3COO)2 + 2HCl → PbCl2 + CH3COOH

Double displacement reaction 

(b) 2Na + 2C2H5OH → 2C2H5ONa + H2 

Displacement reaction 

(c) Fe2O3 + 3CO →2Fe + 3CO2

Redox reaction 

(d) 2H2S + O2 →2S + 2H2O

Redox reaction

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

...