Height of first pole AB = 9 m and
Height of second pole CD = 14 m
Let distance between their tops CA = x m
From A, draw AE || BD meeting CD at E.
Then EA = DB = 12 m CE = CD – ED = CD – AB = 14-9 = 5 m
In right ∆AEC,
AC2 = AE2 + CE2
= 122 + 52
= 144 + 25
= 169
or AC = 13
Distance between pole’s tops is 13 m