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in Application of Derivatives by (46.3k points)

Prove that value of sin2 x (1 + cosx) is maximum x = 1/2.

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Let y = sin2  x.(1 + cosx) …..(1)

Diff.wrt.x,

⇒ dy/dx = sin2 x(- sin x) + (1 + cos x)

⇒ dy/dx = sinx (-sin2 x + 2 cos x + 2 cos2 x) …..(2)

For maxima of minima dy/dx= 0

Hence, at cos x = 1/3 function has maximum value.

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