Use app×
Ask a Question
Join Bloom Tuition
One on One Online Tuition
JEE MAIN 2025 Foundation Course
NEET 2025 Foundation Course
CLASS 12 FOUNDATION COURSE
CLASS 10 FOUNDATION COURSE
CLASS 9 FOUNDATION COURSE
CLASS 8 FOUNDATION COURSE

Factorise : 64a^13b + 343ab^13 .

← Prev Question Next Question →
0 votes
2.8k views
in Mathematics by (106k points)

Factorise : 64a13b + 343ab13 .

Play Quiz Game >

1 Answer

0 votes
by (323k points)
selected by
 
Best answer

64a13b + 343ab13 = ab[64a12 + 343b12] 

= ab[(4a4 ) 3 + (7b4 ) 3 ] 

= ab[4a4 + 7b4 ] [(4a4 ) 2 - (4a4 ) (7b4 ) + (7b4 ) 2 ] 

= ab[4a4 + 7b4 ][16a8 - 28a4b 4 + 49b8 ] 

← Prev Question Next Question →

Find MCQs & Mock Test

  1. JEE Main 2025 Test Series
  2. NEET Test Series
  3. Class 12 Chapterwise MCQ Test
  4. Class 11 Chapterwise Practice Test
  5. Class 10 Chapterwise MCQ Test
  6. Class 9 Chapterwise MCQ Test
  7. Class 8 Chapterwise MCQ Test
  8. Class 7 Chapterwise MCQ Test

Related questions

0 votes
1 answer
Factorise : 1 – 64a^3 -12a + 48a^3
asked Mar 13, 2022 in Polynomials by RohanSolanki (42.6k points)
0 votes
1 answer
Factorise the following: (i) 64a^3 + 21b^3
asked May 22, 2020 in Polynomial by HarshKumar (31.2k points)

Welcome to Sarthaks eConnect: A unique platform where students can interact with teachers/experts/students to get solutions to their queries. Students (upto class 10+2) preparing for All Government Exams, CBSE Board Exam, ICSE Board Exam, State Board Exam, JEE (Mains+Advance) and NEET can ask questions from any subject and get quick answers by subject teachers/ experts/mentors/students.

Categories

User Contribution to Sarthaks eConnect
Managed by Sarthaks Digitizing India
...