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Prove that 3 – √5 is an irrational number?

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Let 3 – √5 is a rational number,we find out such integers numbers a and b (b ≠ 0)

3 – √5 = a/b

3 - a/b = √5

(3b - a)/b = √5

a and b are integer numbers 

So, (3b - a)/b is a rational number.

So, √5 be also a rational number

But this fact is contradicted that √5 is an irrational number.

So our hypothesis is wrong.

3 – √5 is an irrational number.

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