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Find the LCM and HCF of the given pair of integers and check product of two numbers = H.C.F x L. C.M

(i) 26 and 91,

(ii) 510 and 92,

1 Answer

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(i) Given numbers are 26 and 91

Product of factors of common primes (in minimum powers) 26 and 91 

= (13)1 = 13

The product of all prime factors of 26 and 91 in maximum powers.

Hence, (H.CF.) = 13

and (L.C.M.) = 182

Product of both numbers 

= 26 x 91 = 2366

and H.C.F. x L.C.M. 

= 13 x 182 = 2366

Now product of both number 

= H.C.F. x L.C.M.

(ii) Given numbers are 510 and 92

510 = 2 x 3 x 5 x 17 

= (2) x (3) x (5) x (17)

Product of common prime factors of 92 and 510 

= (2)1 = 2.

So, H.C.F. = 2

Product of both numbers 

= (2)2 x (3) x (5) x (17) x (23) 

= 23460

So, L.C.M. = 23460

Product of both numbers 

= 92 x 510 = 46920

and H.C.F. x L.C.M. 

= 2 x 23460 = 46920

So, product of both number 

= H.C.F. x L.C.M.

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