Given : D is any point on side AB of ∆ABC and E and F are two points on side BC. line segment DF, DE and AE are drawn.
To prove : BF/FE= BE/EC
Proof : In ∆BCA,
DE || AC (given)
BE/EC = BD/DA …..(i) (By Basic Prop. Theorem)
Again In ∆BEA, DF || AE (given)
BF/FE = BD/DA …..(ii) (By Basic Prop. Theorem)
From equation (i) and (ii)
BF/FE = BE/EC
