Given: Price of the tractor is ₹12000.
We need to find the total cost of the tractor if he buys it in installments.
Total price = ₹ 12000
Paid amount = ₹ 6000
Unpaid amount = ₹ 12000 – 6000 = ₹ 6000
He pays remaining ₹ 6000 in ‘n’ number of installments of ₹ 500 each.
So, n = 6000/500 = 12
Cost incurred by him to pay remaining 6000 is
The AP will be:
(500 + 12% of 6000) + (500 + 12% of 5500) + … up to 12 terms
500 × 12 + 12% of (6000 + 5500 + … up to 12 terms)
By using the formula,
Sn = n/2 [2a + (n – 1)d]
n = 12, a = 6000, d = -500
S12 = 500×12 + 12/100 × 12/2 [2(6000) + (12 - 1) (-500)]
= 6000 + 72/100 [12000 + 11 (-500)]
= 6000 + 72/100 [12000 – 5500]
= 6000 + 72/100 [6500]
= 6000 + 4680
= 10680
Total cost = 6000 + 10680
= 16680
∴ The total cost of the tractor if he buys it in installment is ₹ 16680.